Holistic Numerical Methods Institute

committed to bringing numerical methods to undergraduates

Multiple Choice Test

Finite Difference Method

 


Q1. The exact solution to the boundary value problem

, and  

for y(4) is

-234.67

0.0000

16.000

37.333


Q2. Given

, , ,

the value of  at y(4) using the finite difference method and a step size of h=4 can be approximated by


Q3. Given

, , ,

 The value of y(4) using the finite difference method with a second order accurate central divided difference method and a step size of h=4 is

 0.000

37.333

-234.67

-256.00


Q4. The transverse deflection u of a cable of length, L, that is fixed at both ends, is given as a solution to

where

T = tension in cable

R = flexural stiffness

q = distributed transverse load

Given L=50", T=200 lbs, q=75lbs/in, R=75x106 lbs-in2, using finite difference method modeling with second order central divided difference accuracy and a step size of h=12.5", the value of the deflection at the center of the cable most nearly is

0.072737"

0.08832"

0.081380"

0.084843"


Q5. The radial displacement, u of a pressurized hollow thick cylinder (inner radius=5″, outer radius=8″) is given at different radial locations.

Radius

Radial Displacement

(in)

(in)

5.0

0.0038731

5.6

0.0036165

6.2

0.0034222

6.8

0.0032743

7.4

0.0031618

8.0

0.0030769

 

The maximum normal stress, in psi, on the cylinder is given by

 

 

The maximum stress, in psi, with second order accuracy is

Hint:     ,

 and

where

  

2079.3

2104.5

2130.7

2182.0


Q6. For a simply supported beam (at x=0 and x=L) with a uniform load q, the vertical deflection v(x) is described by the boundary value ordinary differential equation as

 

            ,

 

where

        E = Young’s modulus of elasticity of beam

        I = second moment of area.

This ordinary differential equation is based on assuming that dv/dx is small.  If dv/dx is not small, then the ordinary differential equation is given by

 

 

 

 

 

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